h^2+28h-3=0

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Solution for h^2+28h-3=0 equation:


Simplifying
h2 + 28h + -3 = 0

Reorder the terms:
-3 + 28h + h2 = 0

Solving
-3 + 28h + h2 = 0

Solving for variable 'h'.

Begin completing the square.

Move the constant term to the right:

Add '3' to each side of the equation.
-3 + 28h + 3 + h2 = 0 + 3

Reorder the terms:
-3 + 3 + 28h + h2 = 0 + 3

Combine like terms: -3 + 3 = 0
0 + 28h + h2 = 0 + 3
28h + h2 = 0 + 3

Combine like terms: 0 + 3 = 3
28h + h2 = 3

The h term is 28h.  Take half its coefficient (14).
Square it (196) and add it to both sides.

Add '196' to each side of the equation.
28h + 196 + h2 = 3 + 196

Reorder the terms:
196 + 28h + h2 = 3 + 196

Combine like terms: 3 + 196 = 199
196 + 28h + h2 = 199

Factor a perfect square on the left side:
(h + 14)(h + 14) = 199

Calculate the square root of the right side: 14.10673598

Break this problem into two subproblems by setting 
(h + 14) equal to 14.10673598 and -14.10673598.

Subproblem 1

h + 14 = 14.10673598 Simplifying h + 14 = 14.10673598 Reorder the terms: 14 + h = 14.10673598 Solving 14 + h = 14.10673598 Solving for variable 'h'. Move all terms containing h to the left, all other terms to the right. Add '-14' to each side of the equation. 14 + -14 + h = 14.10673598 + -14 Combine like terms: 14 + -14 = 0 0 + h = 14.10673598 + -14 h = 14.10673598 + -14 Combine like terms: 14.10673598 + -14 = 0.10673598 h = 0.10673598 Simplifying h = 0.10673598

Subproblem 2

h + 14 = -14.10673598 Simplifying h + 14 = -14.10673598 Reorder the terms: 14 + h = -14.10673598 Solving 14 + h = -14.10673598 Solving for variable 'h'. Move all terms containing h to the left, all other terms to the right. Add '-14' to each side of the equation. 14 + -14 + h = -14.10673598 + -14 Combine like terms: 14 + -14 = 0 0 + h = -14.10673598 + -14 h = -14.10673598 + -14 Combine like terms: -14.10673598 + -14 = -28.10673598 h = -28.10673598 Simplifying h = -28.10673598

Solution

The solution to the problem is based on the solutions from the subproblems. h = {0.10673598, -28.10673598}

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